[FRIAM] Entropy Redux

Pieter Steenekamp pieters at randcontrols.co.za
Wed May 28 00:18:04 EDT 2025


Assuming the pressures were equal at the start, it will slide from the left
(having been compressed) to the right.
>From the ideal gas law PV = nRT, both have equal nRT;s so the one with
smaller V must have higher P and it would then push to the right.

On Wed, 28 May 2025 at 04:59, Nicholas Thompson <thompnickson2 at gmail.com>
wrote:

> Side by side, butt-to-butt, two cylinders of air, of equal volume and
> equal temperature, but different histories. They are separated by a
> frictionless sliding divider which is now pegged.  Before compression or
> heating, both started with air at 10 degrees C, and after compression or
> heating, both arrive at 20 degrees C. The left one has arrived at its
> present temperature and volume by being compressed, the right-hand one
> by having its volume set to the same value as the left and then having
> contents  heated.  All compartments insulated, all manipulations
> quasi-static.  Now, remove the peg, allowing the partition between the two
> parts to slide, one way or the other.  Which way would it slide and why.
> What would your explanation be?  Please don't read others' answers until
> you have submitted your own.
> --
> Nicholas S. Thompson
> Emeritus Professor of Psychology and Ethology
> Clark University
> nthompson at clarku.edu
> https://wordpress.clarku.edu/nthompson
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