[FRIAM] "I have no idea what's going on." -- Towelie

[Marcus Daniels]

I wasn't try to relate it to your first question.   The evidence that degenerate states exist is that SQUID-based quantum computers can and do generate them.   

On 5/22/19, 5:02 PM, "Friam on behalf of uǝlƃ ☣" <friam-bounces at redfish.com on behalf of gepropella at gmail.com> wrote:

    OK. Well, I thought I could've digested the two papers by this time. But I've failed and will probably give up for now. It's still entirely unclear to me how the 3 level system's dark states facilitate the finer-than-diffraction-limited resolution. So, I can't place the OR gate example into the context of the laser lattice and my 1st basic question about energy state transitions via different energy photons.
    
    I believe I grok your point about any given "degenerate" state being "computed over" as if it is or could be real[ized], just so that the solutions are meaningful. But in the context of microscopy, distinguishing things below the resolution allowed by the drive beam, I remain completely lost.
    
    Hopefully, I'll try again soon ... maybe on an airplane flight when I have nothing to distract me. 8^)
    
    On 5/18/19 8:00 AM, Marcus Daniels wrote:
    > Glen writes:
    > 
    > "What evidence is there of degenerate ground states?"
    > 
    > The Hamiltonians for a logical operator like an OR gate need ground-state degeneracies for non-trivial applications.
    > 
    > Configuration Input0 Input1 -> Output
    > A 0 0 -> 0
    > B 0 1 -> 1
    > C 1 0 -> 1
    > D 1 1 -> 1
    > 
    > P(A) = P(B) = P(C) = P(D) = 0.25
    > 
    > If the probabilities (thus energies) were not balanced, then the OR gate could not be inverted in a fair way.   Excited eigenstates typically exist, but they would give configurations that were wrong like "D 0 0 -> 1".  Suppose one wanted to find the key for a complex encryption circuit.  A gate encoding that completely favored one gate, P(X) = 1, would not enable search. 
    
    
    -- 
    ☣ uǝlƃ
    
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