[FRIAM] "I have no idea what's going on." -- Towelie

[Nick Thompson]

Hopefully, I'll try again soon ... maybe on an airplane flight when I have nothing to distract me. 8^)

 

Well, except nothing perhaps but  hurtling at 60 percent of the speed of sound, at ten percent of normal oxygen levels, at 30 degrees below zero packed in with a 160 other sardines in zorris and hawaian shirts, a third of whom are presumably infected with measles. 

 

You can read on airplanes???! 

 

Nick 

 

Nicholas S. Thompson

Emeritus Professor of Psychology and Biology

Clark University

http://home.earthlink.net/~nickthompson/naturaldesigns/

 

 

-----Original Message-----
From: Friam [mailto:friam-bounces at redfish.com] On Behalf Of u?l? ?
Sent: Wednesday, May 22, 2019 5:02 PM
To: FriAM <friam at redfish.com>
Subject: Re: [FRIAM] "I have no idea what's going on." -- Towelie

 

OK. Well, I thought I could've digested the two papers by this time. But I've failed and will probably give up for now. It's still entirely unclear to me how the 3 level system's dark states facilitate the finer-than-diffraction-limited resolution. So, I can't place the OR gate example into the context of the laser lattice and my 1st basic question about energy state transitions via different energy photons.

 

I believe I grok your point about any given "degenerate" state being "computed over" as if it is or could be real[ized], just so that the solutions are meaningful. But in the context of microscopy, distinguishing things below the resolution allowed by the drive beam, I remain completely lost.

 

Hopefully, I'll try again soon ... maybe on an airplane flight when I have nothing to distract me. 8^)

 

On 5/18/19 8:00 AM, Marcus Daniels wrote:

> Glen writes:

> 

> "What evidence is there of degenerate ground states?"

> 

> The Hamiltonians for a logical operator like an OR gate need ground-state degeneracies for non-trivial applications.

> 

> Configuration Input0 Input1 -> Output

> A 0 0 -> 0

> B 0 1 -> 1

> C 1 0 -> 1

> D 1 1 -> 1

> 

> P(A) = P(B) = P(C) = P(D) = 0.25

> 

> If the probabilities (thus energies) were not balanced, then the OR gate could not be inverted in a fair way.   Excited eigenstates typically exist, but they would give configurations that were wrong like "D 0 0 -> 1".  Suppose one wanted to find the key for a complex encryption circuit.  A gate encoding that completely favored one gate, P(X) = 1, would not enable search. 

 

 

--

☣ uǝlƃ

 

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